2010 A-level H2 Mathematics (9740) Paper 2 Question 3 Suggested Solutions

All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.

\frac{dy}{dx} = \frac{3x+4}{2\sqrt{x+2}}

For the curve to have a turning point, \frac{dy}{dx}=0

\Rightarrow 3x+4=0

x = -\frac{4}{3}

y = \pm x \sqrt{x+2}

\frac{dy}{dx}= \pm \frac{3x+4}{2\sqrt{x+2}}

When x=0, \frac{dy}{dx}= \pm sqrt{2}







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