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UGC NET Paper 2: Electronic Science June 2019 Official Paper

Option 3 : 8 kHz

CT 3: Building Materials

2894

10 Questions
20 Marks
12 Mins

__Concept__:

The bandwidth of a PCM system for an encoded signal sampled at a frequency of fs is given by:

Bit rate = n fS

fS = Sampling frequency

n = number of bits used for encoding.

n is related to the number of quantization levels (L) as:

L = 2n

n = log2 L

__Calculation__:

the maximum frequency for the signal will be 4 kHz.

n = 10 bits, R_{b} = 60 Kbits/sec

Bit rate = n fS

f_{s} = 6 kHz

And f_{m} is given as 4 kHz i.e

f_{s} ≥ 2f_{m}

f_{s} ≥ 8 kHz

So, f_{s} = 6kHz leads to undersampling.

Hence, option 1 and 2 can't be correct.

Option 4: f_{s} = 9 kHz leads to oversampling

Hence, option 3 is correct f_{s} = 8 kHz

∴ The appropriate value of the sampling frequency (fs) will be 8 kHz