2010 A-level H2 Mathematics (9740) Paper 1 Question 7 Suggested Solutions

All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.

$\frac{d \theta}{dy} = k(20-\theta)$ where k is a positive constant.

When $\theta = 10, \frac{d\theta}{dt}=1$

$\Rightarrow k = 0.1$

$\int \frac{1}{20-\theta} d\theta = \int 0.1 dt$

$-\mathrm{ln}|20-\theta| = 0.1t + C$

Since $\theta \le 20, -\mathrm{ln}(20-\theta) = 0.1t + C$

When $t = 0, \theta = 10$

$\Rightarrow C = -\mathrm{ln}10$

$\mathrm{ln}(20-\theta) = -0.1t + ln10$

$\theta = 20 - 10 e^{-0.1t}$

When $\theta = 15, t = 6.93\mathrm{~min}$

KS Comments:

Not a tough question, just be care when you draw the graph, consider only the positive t values. Students can omit the module too since $\theta \le 20$ always.

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KS Teng

KS has been teaching H2/H1 Mathematics and IB mathematics for the more than 10 years. Having taught students from all various Junior Colleges, KS adapts to students' abilities and help them better understand the topics. As someone who loves to teach mathematics and sees it as a truly useful tool in life, KS seeks to enable students to appreciate math. Therefore, his tuition mission is to motivate and cultivate students to be independent and confident thinkers.

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April 19th, 2016 01:43 PM

2010 A-level H2 Mathematics (9740) Paper 1 Question 7 Suggested Solutions

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