All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.

(i)

y = \frac{(x-2)^3}{2} - 6

When x = 0, y = -10

When y = 0, \frac{(x-2)^3}{2} = 6

\Rightarrow x-2 = \sqrt[3]{12}

\Rightarrow x = 2 + \sqrt[3]{12}

Coordinates are (0,-10) \text{~and~} (2 + \sqrt[3]{12}, 0)

Function 5i
Function 5i

(ii)

Functions (ii)
Functions (ii)

KS Comments:

Some students wasted time to find the expression f^{-1}, which shows they have poor knowledge. Students should label the axial intercepts coordinates, (0,-10) \text{~and~} (2 + \sqrt[3]{12}, 0).

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