2014 A-level H1 Mathematics (8864) Question 4 Suggested Solutions

All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.

By Pythagoras’ Theorem, (2x)^{2}  + (y-2)^{2} = (2\sqrt{65})^{2}

\therefore, 5x^{2} + y^{2}-2xy = 260


Perimeter = 6x+2y = 60

\Rightarrow 5x^{2} + (30-3x)^{2}-2x(30-3x) = 260

x^{2} -12x +32 = 0

x = 4 ~\mathrm{or}~ x= 8

When x = 4, y = 18

When x = 8, y = 6 < x, which is not possible given the question. Thus, rejected.

\therefore, x=4, y=18

KS Comments

Students need to be alert to reject the appropriate x-value. Alternatively, they can also check the second order derivative to determine which is the suitable x value.

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