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(i)

(ii)
$\frac{dy}{dx}= -e^{1-2x}(-2) = 2 e^{1-2x}$

Sub $(1, 1- \frac{1}{e}), ~ \frac{dy}{dx} = \frac{2}{e}$

Tangent: $y - (1-\frac{1}{e}) = \frac{2}{e}(x-1)$

$\therefore, y = \frac{2}{e}x - \frac{3}{e} +1$