2012 A-level H2 Mathematics (9740) Paper 2 Question 1 Suggested Solutions

All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.

(i)
\frac{dy}{dx} = 16x - 3x^2 + C

y = 8x^2 - \frac{3}{4} x^4 + Cx + D

(ii)

\int \frac{1}{16 - 9u^2} du = \int 1 dt

\frac{1}{3} \times \frac{1}{8} \mathrm{ln} |\frac{4+3u}{4-3u}| = t + C

Let u = 1, t = 0,

C = \frac{1}{24} \mathrm{ln} 7

\Rightarrow \frac{1}{24} \mathrm{ln} |\frac{4+3u}{4-3u}| = t + \frac{1}{24} \mathrm{ln} 7

T = \frac{1}{24} \mathrm{ln} |\frac{4+3u}{7(4-3u)}|

KS Comments:

Students need to be reminded to put modulus due to the presence of ln. The integration formula in (ii) can be found in MF15 too.

Leave a Comment

four × three =

Contact Us

CONTACT US We would love to hear from you. Contact us, or simply hit our personal page for more contact information

Not readable? Change text. captcha txt

Start typing and press Enter to search