Since I’m at the topic of Vectors for most of my JC1 classes, I thought I share an interesting question regarding it. Yes, some students do tell me the questions aren’t really A’levels, but I think it does make you think and this is very important in learning.

Question: Can you place 5 points in three dimensional space such that they are pair wise equidistant?

The answer is no. Consider starting with three pairwise equidistant points with a common distant d between pairs. These are vertices of an equilateral triangle, and they will define a plane. If we add a 4^{th} point that is d units from each of the other three points, then it must be placed at a distance of $latex \frac{\sqrt{3}d}{2} away from the plane on the line normal to the plat that passes through the centre of the triangle. This will give us a tetrahedron.

Hyberbolice Tetrahedon Credits: wolfram.com
Hyberbolice Tetrahedon Credits: wolfram.com

You can consider adding a 5^{th} point at another location that is d from each of the other four. But we will get the same result.

If you figured this out, or understand the explanation, here is a food for thought, in 4-dimensional space, the above will possible 🙂

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