All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.


Fig. 1(i)
Fig. 1(i)

OC = \sqrt{2^2+5^2} = \sqrt{29}

Max. |z| = \sqrt{29}+3

Min. |z| = \sqrt{29}-3

Max. |z-6-i| = \sqrt{(2-6)^2 + (2-1)^2} = \sqrt{17}

KS Comments:

This question is standard tutorial question. Students should not struggle to be able to produce that triangle to apply your trigonometry formulaes. If you have problems drawing a good diagram to scale, I recommend students consider using a graph paper in exams.

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