All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.

(i)

(ii)
$\mathrm{P}(A) = \frac{1}{6} \frac{1}{6} + \frac{1}{6} \frac{1}{6} + \frac{1}{6} \frac{1}{6} +\frac{1}{6} \frac{1}{6} + \frac{1}{6} + \frac{1}{6} =\frac{4}{9}$

(iii)
$\mathrm{P}(A \cap B) = \frac{1}{9}$

(iv)
$\mathrm{P}(A \cup B) = \frac{4}{9} + \frac{2}{6} - \frac{1}{9} = \frac{2}{3}$

(v)
$\mathrm{P} (B| A \prime) = \frac{\mathrm{P}(B \cap A \prime)}{\mathrm{P}(A \prime)} = \frac{\frac{1}{6} \frac{4}{6} + \frac{1}{6} \frac{4}{6}}{5/9} = \frac{2}{5}$