This question is probably very baffling to several students. Many students will exclaim 0!=0 to me, but this is incorrect. To understand why 0!=1, we need to first look at what n! means; n! is the number of ways to arrange n objects in a row. And we all know that n!=1 \times 2 \times 3 \ ... \times n. So shouldn’t 0!=0?

Think about this, the number of ways to arrange 1 object is 1, that is, put the object there by itself. However, the number of ways to arrange 0 object is one! Cos there is nothing to arrange so we still have one way to do it.

Give it some thought and feel free to discuss with me!

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