All solutions here are SUGGESTED. Mr. Teng will hold no liability for any errors. Comments are entirely personal opinions.
This is answers for H2 Mathematics (9740). H2 Mathematics (9758), click here.
Numerical Answers (click the questions for workings/explanation)
Question 1:
; 
Question 2:
or 
Question 3: 2
Question 4:
; translate the graph 4 units in negative y-direction and translate the graph 2 units in positive x-direction.
Question 5:
;
;
or 
Question 6: 
Question 7: 
Question 8:
or
;
; 
Question 9:
;
;
;
; 
Question 10:
;
; 
Question 11:
;
; 



Let 
or 
Since
is non-zero,
.
Let
be the preposition “
” for all 
Let 
LHS 
RHS 
Since LHS = RHS,
is true.
Assume
is true for some
, 

Want to show
is true

LHS



![Rendered by QuickLaTeX.com = 2 - \frac{1}{2^{k+1}} [ 2(k+2) - (k+1)]](http://theculture.sg/wp-content/ql-cache/quicklatex.com-ffff795cc9c4351fef080b8676f03ad2_l3.png)


RHS
Hence, by Mathematical Induction, since
is true,
is true
is true,
is true for all 
(ii)
As 

(i)


for all 
(ii)

Asymptotes are
and 
(iii)
First, translate the graph 4 units in negative y-direction.
Then, translate the graph 2 units in positive x-direction.
(i)
Let

—(1)
—(2)
—(3)

(ii)



Since
is a strictly increasing function with no stationary point. Thus, it can only have one real root.

(iii)


or 
(i)
Set of points lying on the line which passes through a and is parallel to b.
(ii)
Set of points on the plane which has normal vector, n.
is the displacement of the plane from Origin.
(iii)






Since
, line is not parallel to plane, the solution represents the point of intersection between the line and plane.
(a)









or 
(b)
(i)





Comparing real and imaginary parts,

—(1)

—(2)
(1) + (2): 

(ii)

Since all coefficients of
are real,
is a root
is also a root.
![Rendered by QuickLaTeX.com [w - (1+i)][w-(1-i)] = w^2 - 2w + 2](http://theculture.sg/wp-content/ql-cache/quicklatex.com-eb3f4e70d0ce4bc0e03391bb23444f32_l3.png)






(a)
(i)

![Rendered by QuickLaTeX.com U_n = An^2 + Bn -[A(n-1)^2 + B(n-1)]](http://theculture.sg/wp-content/ql-cache/quicklatex.com-753663c18d8c7637cccd57794dead32e_l3.png)

(ii)

—(1)

—(2)
(2) – (1): 

(b)
LHS




![Rendered by QuickLaTeX.com \sum_{r=1}^n r^3 = \frac{1}{4} \sum_{r=1}^n [r^2(r+1)^2 - (r-1)^2 r^2]](http://theculture.sg/wp-content/ql-cache/quicklatex.com-0bfe15349c894ae89df2cf064acb11a6_l3.png)
Using method of difference,


(c)
Let 




Thus, it converges.
From MF26,




For them to intersect,
for some
and 
—(1)
—(2)
—(3)
Solving, 

(ii)
Let
for some 





Since discriminant 
There are no solutions for 

(iii)


Let 

Let 


gives minimum
.

m.
(i)

(ii)

, where
is an arbitrary constant.
When 
When
,



(iii)


, where
is an arbitrary constant.

Let 

When
.

(iv)
As
,

Graph of 11(iv)
Relevant materials
MF26
KS Comments
To be honest, this paper is really the same as the H2 Mathematics (9758). They just rephrased everything. You can see for yourself here.
hello there are no answers 🙁
hi for Q10(ii) would it be sufficient to explain that for both P and Q do not lie on line L hence they are both not points of intersection, PRQ will never be 90degrees?
vectors need not intersect to be perpendicular actually.
Hello, got a quick question! For q6(ii) i remembered my teacher specifically saying r.n = d the ‘d’ is simply a constant with no meaning… so shouldnt displacement of plane from origin be d/(n^)?
Thanks!
yes. but n is given to be a unit vector.. it gives a lot of meaning then
Hi, according to the 9740 papers, may I know what are ur thoughts on the expected range of grade to score A grade? Is 70 marks overall for Ppr 1 & 2 guarantee an A?