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This is answers for H2 Mathematics (9740). H2 Mathematics (9758), click here.
Numerical Answers (click the questions for workings/explanation)
Question 1: ;
Question 2: or
Question 3: 2
Question 4: ; translate the graph 4 units in negative y-direction and translate the graph 2 units in positive x-direction.
Question 5: ; ; or
Question 6:
Question 7:
Question 8: or ; ;
Question 9: ; ; ; ;
Question 10: ; ;
Question 11: ; ;
Let
or
Since is non-zero, .
Let be the preposition “” for all
Let
LHS
RHS
Since LHS = RHS, is true.
Assume is true for some ,
Want to show is true
LHS
RHS
Hence, by Mathematical Induction, since is true, is true is true, is true for all
(ii)
As
(i)
for all
(ii)
Asymptotes are and
(iii)
First, translate the graph 4 units in negative y-direction.
Then, translate the graph 2 units in positive x-direction.
(i)
Let
—(1)
—(2)
—(3)
(ii)
Since is a strictly increasing function with no stationary point. Thus, it can only have one real root.
(iii)
or
(i)
Set of points lying on the line which passes through a and is parallel to b.
(ii)
Set of points on the plane which has normal vector, n.
is the displacement of the plane from Origin.
(iii)
Since , line is not parallel to plane, the solution represents the point of intersection between the line and plane.
(a)
or
(b)
(i)
Comparing real and imaginary parts,
—(1)
—(2)
(1) + (2):
(ii)
Since all coefficients of are real, is a root is also a root.
(a)
(i)
(ii)
—(1)
—(2)
(2) – (1):
(b)
LHS
Using method of difference,
(c)
Let
Thus, it converges.
From MF26,
For them to intersect,
for some and
—(1)
—(2)
—(3)
Solving,
(ii)
Let for some
Since discriminant
There are no solutions for
(iii)
Let
Let
gives minimum .
m.
(i)
(ii)
, where is an arbitrary constant.
When
When ,
(iii)
, where is an arbitrary constant.
Let
When .
(iv)
As ,
Graph of 11(iv)
Relevant materials
MF26
KS Comments
To be honest, this paper is really the same as the H2 Mathematics (9758). They just rephrased everything. You can see for yourself here.
hello there are no answers 🙁
hi for Q10(ii) would it be sufficient to explain that for both P and Q do not lie on line L hence they are both not points of intersection, PRQ will never be 90degrees?
vectors need not intersect to be perpendicular actually.
Hello, got a quick question! For q6(ii) i remembered my teacher specifically saying r.n = d the ‘d’ is simply a constant with no meaning… so shouldnt displacement of plane from origin be d/(n^)?
Thanks!
yes. but n is given to be a unit vector.. it gives a lot of meaning then
Hi, according to the 9740 papers, may I know what are ur thoughts on the expected range of grade to score A grade? Is 70 marks overall for Ppr 1 & 2 guarantee an A?